Integrand size = 22, antiderivative size = 148 \[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\frac {(g x)^{1+m} (d+e x)^n \left (1+\frac {e x}{d}\right )^{-n} \operatorname {AppellF1}\left (1+m,-n,1,2+m,-\frac {e x}{d},-\frac {\sqrt {c} x}{\sqrt {-a}}\right )}{2 a g (1+m)}+\frac {(g x)^{1+m} (d+e x)^n \left (1+\frac {e x}{d}\right )^{-n} \operatorname {AppellF1}\left (1+m,-n,1,2+m,-\frac {e x}{d},\frac {\sqrt {c} x}{\sqrt {-a}}\right )}{2 a g (1+m)} \]
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Time = 0.13 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {926, 140, 138} \[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\frac {(g x)^{m+1} (d+e x)^n \left (\frac {e x}{d}+1\right )^{-n} \operatorname {AppellF1}\left (m+1,-n,1,m+2,-\frac {e x}{d},-\frac {\sqrt {c} x}{\sqrt {-a}}\right )}{2 a g (m+1)}+\frac {(g x)^{m+1} (d+e x)^n \left (\frac {e x}{d}+1\right )^{-n} \operatorname {AppellF1}\left (m+1,-n,1,m+2,-\frac {e x}{d},\frac {\sqrt {c} x}{\sqrt {-a}}\right )}{2 a g (m+1)} \]
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Rule 138
Rule 140
Rule 926
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\sqrt {-a} (g x)^m (d+e x)^n}{2 a \left (\sqrt {-a}-\sqrt {c} x\right )}+\frac {\sqrt {-a} (g x)^m (d+e x)^n}{2 a \left (\sqrt {-a}+\sqrt {c} x\right )}\right ) \, dx \\ & = -\frac {\int \frac {(g x)^m (d+e x)^n}{\sqrt {-a}-\sqrt {c} x} \, dx}{2 \sqrt {-a}}-\frac {\int \frac {(g x)^m (d+e x)^n}{\sqrt {-a}+\sqrt {c} x} \, dx}{2 \sqrt {-a}} \\ & = -\frac {\left ((d+e x)^n \left (1+\frac {e x}{d}\right )^{-n}\right ) \int \frac {(g x)^m \left (1+\frac {e x}{d}\right )^n}{\sqrt {-a}-\sqrt {c} x} \, dx}{2 \sqrt {-a}}-\frac {\left ((d+e x)^n \left (1+\frac {e x}{d}\right )^{-n}\right ) \int \frac {(g x)^m \left (1+\frac {e x}{d}\right )^n}{\sqrt {-a}+\sqrt {c} x} \, dx}{2 \sqrt {-a}} \\ & = \frac {(g x)^{1+m} (d+e x)^n \left (1+\frac {e x}{d}\right )^{-n} F_1\left (1+m;-n,1;2+m;-\frac {e x}{d},-\frac {\sqrt {c} x}{\sqrt {-a}}\right )}{2 a g (1+m)}+\frac {(g x)^{1+m} (d+e x)^n \left (1+\frac {e x}{d}\right )^{-n} F_1\left (1+m;-n,1;2+m;-\frac {e x}{d},\frac {\sqrt {c} x}{\sqrt {-a}}\right )}{2 a g (1+m)} \\ \end{align*}
\[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx \]
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\[\int \frac {\left (g x \right )^{m} \left (e x +d \right )^{n}}{c \,x^{2}+a}d x\]
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\[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\int { \frac {{\left (e x + d\right )}^{n} \left (g x\right )^{m}}{c x^{2} + a} \,d x } \]
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Timed out. \[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\text {Timed out} \]
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\[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\int { \frac {{\left (e x + d\right )}^{n} \left (g x\right )^{m}}{c x^{2} + a} \,d x } \]
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\[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\int { \frac {{\left (e x + d\right )}^{n} \left (g x\right )^{m}}{c x^{2} + a} \,d x } \]
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Timed out. \[ \int \frac {(g x)^m (d+e x)^n}{a+c x^2} \, dx=\int \frac {{\left (g\,x\right )}^m\,{\left (d+e\,x\right )}^n}{c\,x^2+a} \,d x \]
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